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B b v V “

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sin

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s

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b ×

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r ∠ 

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=

× × ×

4 *s 30 )*( 30 + 10 * 3 )=

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×

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c • “

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d e

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f

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6 + 2

'

3

f

5.913591358

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b

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f

1 {5

b

1 - 4 ' 5 =

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f

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7

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7

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b 2 ' 3 + 1 ' 2 = 7 {6

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1

2

b 4 - 3 ' 1 ' 2 = 1 {2

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f

1(

× 150 * 20 1((%)= 30

660 / 880 1((%) =

75

2500 + 2500 * 15 1((%)=

2875

3500 - 3500 * 25 1((%)=

2625

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2 $ 20 $ 30 $+ 0 $ 39 $ 30 $=

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123

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tl(M) 35

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–1

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r

= 90

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g

= 45

e

5

×

1N(SETUP)7(Sci)3

B 1i(%) 5 e* 2 =

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2

b 1i(%) 5 )* 2 = 2.97×10

2

11

22

33

44

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l 1000 )= 3

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e

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0

×

3

B 1.2 * 10 6 3 = 1200

2+2

B( 1 + 1 )6 2 + 2 = 16

2 3

( 5 x)W= 15625

B 16(") 5 e 32 = 2

b 516(") 32 )= 2

'

×

'

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3

'

2

1=

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b ! 2 )* 3 = 4.243

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v

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r=2,  =45

b 1+(Pol)! 2 )1)(,)! 2 ))= r= 2

 = 45

'

v

B 1-(Rec)! 2 e1) (,) 45 )=

X=1, Y=1

( 5 + 3 )1E(x !)= 40320

×

B D 2 - 7 e* 2 =

10

b D 2 - 7 )* 2 = 10

1000 1.(Ran#)= 459

= 48

= 117

S.(RanInt) 1 1)(,) 6 )= 2

= 6

= 1

10 1*(n Pr ) 4 = 5040

10 1/(n Cr ) 4 = 210

55

66

77

88

99

1010

1111

1212

1313

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×

× b

1N(SETUP)6(Fix)3 10 / 3 * 3 = 10.000

10(Rnd) 10 / 3 )* 3 = 9.999

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1

y x

2

y x x

2

3

2

y x

4

e y e

B

x

5

e

ab y

x

6 •

y x

B

7 •

y x

8

1 8

11 1

11 2

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170 = 173 = 179 =ce

66 = 68 = 75 =

1414

11

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m 1m 1t

=

Y

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11 3 2

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2

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x

2

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2

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3

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4

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11 6 1 4

r m n

11 5 1 5

m m n

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x

n n

1N(SETUP)c3(STAT)1(ON)

1N(SETUP)c4(STAT)1(ON)

N2(STAT)1(1-VAR)

1 = 2 = 3 = 4 = 5 =ce

1 = 2 = 3 = 2 =

A11(STAT)4(Var)2(o)=

A11(STAT)4(Var)3(σ

x)=

22

STATSTAT

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x y

1N(SETUP)c3(STAT)2(OFF)

1N(SETUP)c4(STAT)2(OFF)

1N(SETUP)6(Fix)3

N2(STAT)2(A+BX)

20 = 110 = 200 = 290 =ce

3150 = 7310 =8800 = 9310 =

A11(STAT)5(Reg)3(r)=

A11(STAT)1(Type)4(In X)

A11(STAT)5(Reg)3(r)=

A11(STAT)5(Reg)1(A)=

A11(STAT)5(Reg)2(B)=

y x

x x x

y

y x

3 3

A 160 11(STAT)5(Reg)5(n)=

N3

1

2

3

2

33

STAT

FIX

STAT

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4

3 2

•

x

2

x 3

a b c = =- =

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=

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m 1m

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• = =

• c f

• A

• “ ” '

•

N3

x y x y

N3(EQN)1(a

n

X + b

n

Y = c

n

)

1 = 2 = 3 =

2 = 3 = 4 =

=

(X=) −1

c (Y=) 2

x y z x y z x y z

N3(EQN)2(a

n

X + b

n

Y + c

n

Z = d

n

)

1 =- 1 = 1 = 2 =

1 = 1 =- 1 =0 =

- 1 = 1 = 1 = 4 =

=

(X=) 1

c (Y=) 2

c (Z=) 3

x

2

x B

N3(EQN)3(aX

2

+ bX + c = 0)

1 = 1 = 3 ' 4 ==

(X

1

=)

1

2

+

–

'

2

i

c

(X

2

=)

1

2

–

'

2

i

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