Casio fx-570c 取扱説明書

fx-570MS

fx-991MS

CA 310029-001V06

J

http://www.casio.co.jp/edu/

SA0403-E Printed in China

151-8543 1-6-2

1

Eng

↔

n

2

fx-95MS/fx-100MS/fx-570MS/

fx-912MS (fx-115MS)/fx-991MS

3

CMPLX

fx-570MS/fx-991MS

<fx-570MS/fx-991MS>

COMP F 1

CMPLX F 2

SD F F 1

REG F F 2

nBASE F F 3

EQN F F F 1

MAT F F F 2

VCT F F F 3

FDeg, Rad

A B 2(Mode) =

COMP

Deg

Norm 1/Eng OFF

abi

4

COMP

ab/c

Dot

n

BASE Eng

BASE

Disp

COMP CMPLX SD REG

SD REG

COMP CMPLX Deg Rad

Gra

COMP

COMP ............................................................ F 1

1 + 1 =2 + 2 =3 + 3 =

3[

]1 + 1 A [(COPY)

1 + 1 : 2 + 2 : 3 + 3

3

5

=

179

COMP CMPLX

-Y = X2 + 3X – 12 X 7

Y

58

X 8

Y

76

p y p u p x K + 3 p x , 12

C

X? 7 7 =

X? 8 C 8 =

-A

B C

B=14 mC=2 sD=9.8 m s2

A

A=

16.8

B  AC – DC2

CMPLX

COMP

1

2

6

COMP

p 2 p u p 1 - p k ,

R 1 \ 2 T - p h - p k K

A I

(B?) 14 =

(A?) ]

(C?) 2 =

(D?) 9 l 8 =

[ [

(A?) A I

u

uy = sin x

u

y exy1/x

uyx

0

COMP

COMP ............................................................ F 1

7

Eng

F

1

Disp

1Eng 1 2

1Eng ON Eng “Eng”

2Eng OFF Eng “Eng”

Eng Eng 9

Eng

k( ) Ak103

M( ) AM106

G( ) Ag109

T( ) At1012

m( ) Am10

-

3

µ

( ) AN10

-

6

n( ) An10

-

9

p( ) Ap10

-

12

f( ) Af10

-

15

Eng 11000

Eng

1100m ( ) × 5

µ

( ) = 500n ( )

F ..... 1Disp 1

0.

Eng

100 A m - 5 A N =

500.

1

m

×

5 n

µ

29 ÷ 10 = 0.9m ( )

F ..... 1Disp 1

0.

Eng

COMP

CMPLX

EQN

8

CMPLX

9 \ 10 =

900.

9

1 m

A P

0.9

J

900.

9

1 m

31k ( ) × 1k ( ) = 1M ( )

F ..... 1Disp 1

0.

Eng

1 A k - 1 A k =

1.

1

k

×

1

k M

41T ( ) × 1000000000 = 1 × 1021

F ..... 1Disp 1

0.

Eng

1 A t - 1000000000 =

1.

1

T

×

1

21

Eng 11000

CMPLX

CMPLX ........................................................... F 2

Deg,Rad,Gra

CMPLX A, B, C, M

D, E, F, X, Y

“R↔I”

Ar

CMPLX

Eng

9

-2+3i)4+5i)

6



8

i

6 2 + 3 i + 4 + 5 i =

8iA r

z abi

r



r



13+4i r



Deg r

5



53.13010235

°

(r 

5

) A A R 3 + 4 i T =

(





53.13010235

°)A a R 3 + 4 i T =

r



2 2 ⬔45 

1

 iL2AQ45 =

(Deg )A r

↔

r



Ar

10

BASE

-1

 i↔

1.414213562 ⬔45

(Deg )1 + i A Y = A r

L 2 A Q 45 A Z = A r

abi

r



F

1

Disp

1r1 2

1(a+bi):

2(r⬔



): r⬔



z = a+bi z = a–bi

-1.23 + 2.34i

1.23 – 2.34

i

A S R 1 l 23 + 2 l 34 i T =

A r

n

nBASE

BASE ........................................................ F F 3

10 2816

n

11

2 8 16 2

n

and or xor

xnor Not Neg

1101112 + 1101022

(

1100012

)

t b

0.

b

10111 + 11010 =

276548 ÷ 1210 8

(

5168

)

t o

0.

o

l l l 4(o)

7654 \

l l l 1(d)12 =

312016

or 1101216 10

(

12d16

,

30110

)

t h

0.

H

120 l 2(or)

l l l 3(b)1101=

K

42210 2 8 16

(

101102 , 268 , 16 16

)

2t b

0.

b

21000000000 <x<1111111111

0<x<0111111111

84000000000 <x<7777777777

0<x<3777777777

10

-

2147483648 <x<2147483647

16 80000000 <x<FFFFFFFF

0<x<7FFFFFFF

2

16

8

10

12

SD

REG

SD

l l l 1(d) 22 =

10110.

b

8o

26.

o

16 h

16.

H

551310 2

2t b

0.

b

l l l 1(d) 513 =

aMthERROR

b

Math ERROR

SD

SD ............................................................ F F 1

SD REG | S

A D

1

2

3

4

P

(

Q

(

R

(

→

t

1 4

P(t)R(t)Q(t)

13

COMP

-x

x = 53 (

→

t

)

P(t

)

55, 54, 51, 55, 53, 53, 54, 52

(→t = 

0.284747398

, P(t) =

0.38974

)

55 S 54 S 51 S 55 S

53 S S 54 S 52 S

53 A D 4(→t) =

A D 1( P( ) D 0.28 F =

COMP

COMP ............................................................ F 1

x

a x ∆x3

A J P a P ∆x T

- y 3x2– 5x+ 2 x2

x∆x=2 × 10–4

7

A J 3 p x K , 5 p x + 2 P 2 P

2 e D 4 T =

∆x

Rad

Radian

14

COMP

MAT

COMP

COMP ............................................................. F 1

x

a, b n N

= 2n4

d

P a P b P n F

-∫ (2 x 2 + 3 x + 8)

dx =

150.6666667

n = 6

d 2 p x K + 3 p x +

8 P 1 P 5 P 6 T =

n1~9

Rad

Radian

3 3 3

MAT

MAT .................................................... F F F 2

5

1

15

A, B, C 3

MatAns

2

1

Aj1Dim A, B, C

t

Aj2Edit A, B, C

- A = B =

12

4 0

–2 5

[

]

[ ]

( )

3–8 5

–4 0 12

12 –20 –1

[ ]

–1 0 3

2–4 1

M

atA

23

2 3

16

( A 32) A j 1(Dim) 1(A) 3 = 2 =

( ) 1 = 2 = 4 = 0 = D 2 = 5 = t

( B 23) A j 1(Dim) 2(B) 2 = 3 =

( ) D 1 = 0 = 3 = 2 = D 4 = 1 = t

(MatAMatB) A j 3(Mat) 1(A) -

A j 3(Mat) 2(B) =

- C = 33C

( C 22) A j 1(Dim) 3(C) 2 = 2 =

( ) 2 = D 1 = D 5 = 3 = t

(3MatC) 3 - A j 3(Mat) 3(C) =

- A =

73

( A 33) A j 1(Dim) 1(A) 3 = 3 =

( ) 2 = D 1 = 6 = 5 = 0 = 1 =

3 = 2 = 4 = t

(DetMatA) A j r 1(Det)

A j 3(Mat) 1(A) =

[ ]

(

)

2–1

–5 3

6–3

–15 9

[ ]

2–1 6

501

324

17

- B =

( B 23) A j 1(Dim) 2(B) 2 = 3 =

( ) 5 = 7 = 4 = 8 = 9 = 3 = t

(TrnMatB) A j r 2(Trn)

A j 3(Mat) 2(B) =

- C =

( C 33) A j 1(Dim) 3(C) 3 = 3 =

( ) D 3 = 6 = D 11 = 3 = D 4 =

6 = 4 = D 8 = 13 = t

(MatC–1)A j 3(Mat) 3(C) a =

0

[

]

( )

58

7 9

4 3

[ ]

–3 6 –11

3–4 6

4–8 13

[ ]

( )

–0.4 1 –0.8

–1.5 0.5 –1.5

–0.8 0 –0.6

[ ]

( )

[ ]

574

893

18

[ ]

(

)

0.4 1 0.8

1.5 0.5 1.5

0.8 0 0.6

VCT

-

(AbsMatAns) A A A j 3(Mat) 4(Ans) =

3 3

VCT

VCT .................................................... F F F 3

A,B,C 3

VctAns

Az1Dim A, B, C

0.

Vc tA1

19

er

t

Az2Edit A, B, C

-A= 1 –2 3 B= 4 5 –6

(5 3 –3)

(3 A) A z 1(Dim) 1(A) 3 =

( ) 1 = D 2 = 3 = t

(3 B) A z 1(Dim) 2(B) 3 =

( ) 4 = 5 = D 6 = t

(VctA + VctB) A z 3(Vct) 1(A) +

A z 3(Vct) 2(B) =

-C= –7.8 9 5 5C

(–39 45)

(2 C) A z 1(Dim) 3(C) 2 =

( ) D 7 l 8 = 9 = t

(5VctC) 5 - A z 3(Vct) 3(C) =

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